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For the HCN Lewis structure, calculate the total number of valence electrons for the HCN molecule. After determining how many valence electrons there are in HCN, place them around the central atom to complete the octets. Be sure to use the number of available valence electrons you found earlier. There are 10 valence electrons for the HCN Lewis structure. HCN is also called Hydrogen cyanide. Carbon is the less electronegative so we'll place it at the center of the N2O3 Lewis structure. Note: Hydrogen (H) atoms always go on the outside of a Lewis structure. In order to make sure the outer shell of the Carbon (C) atoms are full you will need to form a triple bond with the Nitrogen (N) atom in this Lewis structure. ----- Steps to Write Lewis Structure for compounds like HCN ----- 1. Find the total valence electrons for the HCN molecule. 2. Put the least electronegative atom in the center. Note: Hydrogen (H) always goes outside. 3. Put two electrons between atoms to form a chemical bond. 4. Complete octets on outside atoms. 5. If central atom does not have an octet, move electrons from outer atoms to form double or triple bonds. ----- Lewis Resources ----- • Lewis Structures Made Simple: https://youtu.be/1ZlnzyHahvo • More practice: https://youtu.be/DQclmBeIKTc • Counting Valence Electrons: https://youtu.be/VBp7mKdcrDk • Calculating Formal Charge: https://youtu.be/vOFAPlq4y_k • Exceptions to the Octet Rule: https://youtu.be/Dkj-SMBLQzM Lewis Structures are important to learn because they help us understand how atoms and electrons are arranged in a molecule, such as Hydrogen cyanide. This can help us determine the molecular geometry, how the molecule might react with other molecules, and some of the physical properties of the molecule (like boiling point and surface tension). Chemistry help at https://www.Breslyn.org
